1200=2x^2

Solution for 1200=2x^2 equation:

1200=2x^2

We move all terms to the left:

1200-(2x^2)=0

a = -2; b = 0; c = +1200;
Δ = b2-4ac
Δ = 02-4·(-2)·1200
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{6}}{2*-2}=\frac{0-40\sqrt{6}}{-4}
=-\frac{40\sqrt{6}}{-4}
=-\frac{10\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{6}}{2*-2}=\frac{0+40\sqrt{6}}{-4}
=\frac{40\sqrt{6}}{-4}
=\frac{10\sqrt{6}}{-1}
$